Here are some calculations for a rope labyrinth. A classical 7-circuit with paths three feet wide (hence, a labyrinth 45 feet in diameter) requires 600 feet of rope. That means 600 feet of line. With two foot paths and a diameter of 30 feet, it takes 400 feet of rope. With one foot paths, it takes 200 feet. So, as you can see, 200 feet per one foot of path width. Stated another way, the rope length is 13 1/3 times the diameter of the labyrinth. In both cases, the length of the line is 13.33 times the diameter of the labyrinth. This calculation is for the length of line, or rope. To determine how many rocks or bricks, estimate the size and spacing and divide that into the length of the line. So, if you have 400 feet of line and your rocks are six inches in diameter, you will need 800 of them. Of course, you could space them out a little so that they aren't touching and thereby use fewer.
Walking the paths, you must take into
consideration that some people are going in and others coming out. Hence,
there is two-way traffic on the paths. I find that there is no need to
regulate the traffic on the labyrinth. People do it automatically. A related
issue, however, is the size of the center. The classical labyrinth doesn't
really have a center. The path just ends in the middle. So, when a number
of people are walking, as soon as someone reaches the center, it is necessary
to turn and walk back out. However, it is possible to make the center
larger in a classical labyrinth. In such a case, people can then stop
and spend some time in the center. That's usually how we make the classical
pattern. Instructions on how to do that are in our manual, |

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